Александрова формула 2024

${}^{40}_{19}\textrm{K}+e^-\rightarrow {}^{40}_{18}\textrm{Ar} + \nu_e,$

${}^{40}_{19}\textrm{K}\rightarrow {}^{40}_{18}\textrm{Ar} + e^+ + \nu_e,$

${}^{40}_{19}\textrm{K}\rightarrow {}^{40}_{20}\textrm{Ca} + e^- + \bar\nu_e.$

$\frac{dN}{dt} = -\lambda N,$